Step-by-step explanation:
Answer:
(a) How farther did Soni hop than Nancy?
(b) What is the total distance covered by Seema and Megha?
(c) Who walked farther, Nancy or Megha?
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Step-by-step explanation:
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Class 6
>>Maths
>>Fractions
>>Operations on Fractions
>>Four friends had a competition to see ho
Question
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Four friends had a competition to see how far they could hop on one foot. the table given shows the distance covered by each.
Name Seema Nancy Megha Soni
Distance covered (km)
25
1
32
1
40
1
20
1
(a) How farther did Soni hop than Nancy?
(b) What is the total distance covered by Seema and Megha?
(c) Who walked farther, Nancy or Megha?
Medium
Solution
verified
Verified by Toppr
(a) Distance covered by Soni =
20
1
km
Distance covered by Nancy =
32
1
km
∴ Difference between Soni's and Nancy's hop =
20
1
−
32
1
=
160
8−5
=
160
3
km
(b) Distance covered by Seema =
25
1
km
Distance covered by Megha =
40
1
Total distance covered by Seema and Megha =
25
1
+
40
1
=
200
8+5
=
200
13
km
(c) Distance covered by Nancy =
32
1
km=
160
5
km
distance covered by Megha =
40
1
km=
16
4
km
Comparing these numbers, we get
160
5
>
16
4
∴
32
1
>
40
1
Hence, Nancy walked further.
Verified answer
Answer:
(a) How farther did Soni hop than Nancy?
(b) What is the total distance covered by Seema and Megha?
(c) Who walked farther, Nancy or Megha?
Step-by-step explanation:
(a) How farther did Soni hop than Nancy?
(b) What is the total distance covered by Seema and Megha?
(c) Who walked farther, Nancy or Megha?