Now, an object is placed in front of the convex lens such that the corresponding image is produced after refraction through the lens.
Now, there are infinite number of light rays originating from the object which will undergo refraction and converge to produce the corresponding image.
As a result of the hole, a few light rays will not be able to undergo the required refraction.
Hence, the light intensity of the image will decrease. The image will now look a little dull.
But image characteristics (i.e. position and size) will remain unchanged.
Now, an object is placed in front of the convex lens such that the corresponding image is produced after refraction through the lens.
Now, there are infinite number of light rays originating from the object which will undergo refraction and converge to produce the corresponding image.
As a result of the hole, a few light rays will not be able to undergo the required refraction.
Hence, the light intensity of the image will decrease. The image will now look a little dull.
But image characteristics (i.e. position and size) will remain unchanged.
Answers & Comments
Image intensity decreases.
But why?
Explanation:
Image intensity decreases.
But why?
First of all, a hole is made in a convex lens.
Now, an object is placed in front of the convex lens such that the corresponding image is produced after refraction through the lens.
Now, there are infinite number of light rays originating from the object which will undergo refraction and converge to produce the corresponding image.
As a result of the hole, a few light rays will not be able to undergo the required refraction.
Hence, the light intensity of the image will decrease. The image will now look a little dull.
But image characteristics (i.e. position and size) will remain unchanged.
\star⋆ Hope It Helps.