[tex]\large\tt{\colorbox{violet}{\colorbox{indigo}{\colorbox{blue}{\colorbox{green}{\colorbox{yellow}{\colorbox{orange}{\colorbox{red}{\colorbox{black}{ANSWER}}}}}}}}}[/tex]
[tex] \tt \: r = 2.1 \: m \\ \\ \tt \: capacity(volume) \: of \: hemispherical \: tank \: = \\ \\ \tt \: v = \frac{2}{3} \pi {r}^{3} \\ \\ \tt v = \frac{2}{3} \times \frac{22}{7} \: \times 2.1 \:\times 2.1 \times 2.1 \\ \\ \tt \: v = 19.404\: m {}^{3} [/tex]
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[tex]\large\tt{\colorbox{violet}{\colorbox{indigo}{\colorbox{blue}{\colorbox{green}{\colorbox{yellow}{\colorbox{orange}{\colorbox{red}{\colorbox{black}{ANSWER}}}}}}}}}[/tex]
[tex] \tt \: r = 2.1 \: m \\ \\ \tt \: capacity(volume) \: of \: hemispherical \: tank \: = \\ \\ \tt \: v = \frac{2}{3} \pi {r}^{3} \\ \\ \tt v = \frac{2}{3} \times \frac{22}{7} \: \times 2.1 \:\times 2.1 \times 2.1 \\ \\ \tt \: v = 19.404\: m {}^{3} [/tex]