Answer:
r=5cm, thickness of steel sheet =0.25cm
⇒ R=5cm+0.25cm=5.25cm
outer curved surface area of the bowl =2πR ²
=2× 722 × 100/525 × 100/525
cm ²
=173.25cm ²
Step-by-step explanation:
i hope its help to you
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Answers & Comments
Answer:
r=5cm, thickness of steel sheet =0.25cm
⇒ R=5cm+0.25cm=5.25cm
outer curved surface area of the bowl =2πR ²
=2× 722 × 100/525 × 100/525
cm ²
=173.25cm ²
Step-by-step explanation:
i hope its help to you
Answer:
Mark me brain list please