A glass stopper of 20 cm^3 volume and weight as 50 g-wt, as observed by using a spring balance, is taken and immersed completely in tap water. What will be the amount of up thrust and apparent weight of glass stopper?
Add an Answer
More Questions From This User See All
Answers & Comments
Upthrust force acting on body = Weight of water displaced by the body
As stopper volume = 20 cm^3 thus it can only displace 20 cm^3 of tap water
Also we know density of water = 1 g/cm^3
Therefore the weight of water displaced = 1×20 -20g
(Weight = Density × Volume )
Thus Upthrust = 20g or .2N (force = mass × gravitational acceleration)
NOTE: Here I taken gravitational acceleration = 1 O m/s^2
Now,weight of stopper will be reduced by the upthrust by 20g as it act against the body weight
Thus, Apparent Weight = 50 -20= 30g
ALL THE BEST FOR YOUR EXAM
Explanation:
The three most common methods are basin irrigation, border irrigation and furrow irrigation. Water is typically introduced at the highest point or along the edge of a field, which allows covering the field by overland flow.