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SOLUTION:

Step 1: List the given values.

[tex]\begin{aligned} & P_1 = \text{0.970 atm} \\ & V_1 = \text{725 mL} \\ & P_2 = \text{0.541 atm} \end{aligned}[/tex]

Step 2: Calculate the final pressure by using Boyle's law.

[tex]\begin{aligned} P_1V_1 & = P_2V_2 \\ P_2V_2 & = P_1V_1 \\ \frac{P_2V_2}{P_2} & = \frac{P_1V_1}{P_2} \\ V_2 & = \frac{P_1V_1}{P_2} \\ & = \frac{(\text{0.970 atm})(\text{725 mL})}{\text{0.541 atm}} \\ & = \boxed{\text{1,300 mL}} \end{aligned}[/tex]

Hence, the final volume of the gas is 1,300 mL.

[tex]\\[/tex]

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