Answer:

p_(1)=760mm Hg.V_(1)=600 mL`

`T_(1)2=25+273=298K`

`V_(2)=640mL and T_(2)-10+273=283K`

According to Combined gas law

`(p_(1)V_(1))/(T_(1))=(p_(2)V_(2))/(T_(2))`

`rArrp_(2)=(p_(1)V_(1)T_(1))/(T_(2))`

`rArrp_(2)=((760mmHg)xx(600mL)xx(283K))/((640mL)xx(298K))`

= 676.6 mm Hg

Explanation:

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