Step 1: List the given values.
To convert the temperature from degree Celsius to kelvin, add 273.15 to the temperature expressed in degree Celsius.
[tex]\begin{aligned} & V_1 = \text{0.78 L} \\ & T_1 = 20.1^{\circ}\text{C} = \text{293.25 K} \\ & T_2 = 36.5^{\circ}\text{C} = \text{309.65 K} \end{aligned}[/tex]
Step 2: Calculate the final volume by using Charles' law.
[tex]\begin{aligned} \frac{V_1}{T_1} & = \frac{V_2}{T_2} \\ V_2T_1 & = V_1T_2 \\ \frac{V_2T_1}{T_1} & = \frac{V_1T_2}{T_1} \\ V_2 & = \frac{V_1T_2}{T_1} \\ & = \frac{(\text{0.78 L})(\text{309.65 K})}{\text{293.25 K}} \\ & = \boxed{\text{0.82 L}} \end{aligned}[/tex]
Hence, the volume of the gas is 0.82 L.
[tex]\\[/tex]
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SOLUTION:
Step 1: List the given values.
To convert the temperature from degree Celsius to kelvin, add 273.15 to the temperature expressed in degree Celsius.
[tex]\begin{aligned} & V_1 = \text{0.78 L} \\ & T_1 = 20.1^{\circ}\text{C} = \text{293.25 K} \\ & T_2 = 36.5^{\circ}\text{C} = \text{309.65 K} \end{aligned}[/tex]
Step 2: Calculate the final volume by using Charles' law.
[tex]\begin{aligned} \frac{V_1}{T_1} & = \frac{V_2}{T_2} \\ V_2T_1 & = V_1T_2 \\ \frac{V_2T_1}{T_1} & = \frac{V_1T_2}{T_1} \\ V_2 & = \frac{V_1T_2}{T_1} \\ & = \frac{(\text{0.78 L})(\text{309.65 K})}{\text{293.25 K}} \\ & = \boxed{\text{0.82 L}} \end{aligned}[/tex]
Hence, the volume of the gas is 0.82 L.
[tex]\\[/tex]
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