A function f from integers to integers is defined as
n+3, when n is odd integer
f(n) = n 2 when n is even integer
Suppose k is an integer and f(k) = 4. Then the sum of possible values of k is
n+3, when n is odd integer
f(n) = n 2 when n is even integer
Suppose k is an integer and f(k) = 4. Then the sum of possible values of k is
Answers & Comments
Answer:
Correct option is B)
Since k is odd,
f(k)=k+3
Now k+3 is even.
Hence
f(f(k))=
2
k+3
.
Now k+3 is always divisible by 4 for all kϵoddnumber.
Hence
2
k+3
is even.
Then
f(f(f(k)))=
4
k+3
=27
k+3=108
k=105
Hence sum of the digits is 6.