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llJeonstheticll
@llJeonstheticll
October 2023
1
4
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a force of 16n acts on a area of 50cm² . what is the magnitude of pressure in pascal's law?
Question no. 4 pls
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Mysteryboy01
Verified answer
Given :
[tex]Force = 16 \: N \\ \\ Area = 50 \: {cm}^{2} \\ \\ = 50 \times {10}^{ - 4} \: {m}^{2} [/tex]
To Find :
[tex]The \: Pascal [/tex]
Formula used :
[tex]Pressure = \frac{Force}{Area} \\ [/tex]
Solution Explanation :
[tex]Pressure = \frac{Force}{Area} \\ \\ = \frac{16}{50 \times {10}^{ - 4} } \\ \\ = \frac{16 \times {10}^{4} }{50} \\ \\ = \frac{16 \times10,000 }{50} \\ \\ = \frac{1,60,000}{50} \\ \\ = 3,200 \: Pa[/tex]
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Answers & Comments
Verified answer
Given :
[tex]Force = 16 \: N \\ \\ Area = 50 \: {cm}^{2} \\ \\ = 50 \times {10}^{ - 4} \: {m}^{2} [/tex]
To Find :
[tex]The \: Pascal [/tex]
Formula used :
[tex]Pressure = \frac{Force}{Area} \\ [/tex]
Solution Explanation :
[tex]Pressure = \frac{Force}{Area} \\ \\ = \frac{16}{50 \times {10}^{ - 4} } \\ \\ = \frac{16 \times {10}^{4} }{50} \\ \\ = \frac{16 \times10,000 }{50} \\ \\ = \frac{1,60,000}{50} \\ \\ = 3,200 \: Pa[/tex]