Answer:
A force is applied on a body of mass 20 kg moving with a velocity of 40 M s-1 in 2 sec . Calculate the work done by the body .
Force =m
t
(v−u)
=m⋅a
Displacement =
2a
(v
2
−u
)
Word done (W) = Force × Displacement
=m⋅a⋅
W =
1
m(v
×20×(2500−1600)
=
×20×900
=9000J
Therefore, the work done to attain the final velocity is 9000J
Explanation:
It is a four-sided quadrilateral whose area formula is expressed as, product of its base and height, i.e., A = base × height square units.
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Verified answer
Answer:
A force is applied on a body of mass 20 kg moving with a velocity of 40 M s-1 in 2 sec . Calculate the work done by the body .
Force =m
t
(v−u)
=m⋅a
Displacement =
2a
(v
2
−u
2
)
Word done (W) = Force × Displacement
=m⋅a⋅
2a
(v
2
−u
2
)
W =
2
1
m(v
2
−u
2
)
W =
2
1
×20×(2500−1600)
=
2
1
×20×900
=9000J
Therefore, the work done to attain the final velocity is 9000J
Explanation:
It is a four-sided quadrilateral whose area formula is expressed as, product of its base and height, i.e., A = base × height square units.