A first order reaction is 50% in 80 minutes and in 10 mintues at 320 k calculate the activation energy (Ea) for the reaction. R=8.314 j kelvin mol Log 2 = 0.30 log 3 = 0.47 log 4 =0.60 Answer
Showing results for A first order reaction is 50% in 80 minutes and in 10 minutes at 320 k calculate the activation energy (Ea) for the reaction. R=8.314 j kelvin mol Log 2 = 0.30 log 3 = 0.47 log 4 =0.60 Answer
Search instead for A first order reaction is 50% in 80 minutes and in 10 mintues at 320 k calculate the activation energy (Ea) for the reaction. R=8.314 j kelvin mol Log 2 = 0.30 log 3 = 0.47 log 4 =0.60 Answer
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Answer:
Showing results for A first order reaction is 50% in 80 minutes and in 10 minutes at 320 k calculate the activation energy (Ea) for the reaction. R=8.314 j kelvin mol Log 2 = 0.30 log 3 = 0.47 log 4 =0.60 Answer
Search instead for A first order reaction is 50% in 80 minutes and in 10 mintues at 320 k calculate the activation energy (Ea) for the reaction. R=8.314 j kelvin mol Log 2 = 0.30 log 3 = 0.47 log 4 =0.60 Answer