x = bolt manufactured by company A.

y = bolt manufactured by company B.

z = bolt manufactured by company C.

w = defective bolt drawn.

P(x)= 103

,P(y)= 21

,P(z)= 51

P(w∣x)= 1003

,P(w∣y)= 1004

,P(w∣z)= 1001

Probability that defective bolt is drawn from machine B.

P(y∣w)=

P(x).P(w∣x)+P(y).P(w∣y)+P(z).P(w∣z)

P(y).P(w∣y)

P(y∣w)= 3120

Probability that it is not manufactured by B =1− 3120 = 3111

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pls mark as brainliests answer

Answer:

the final answer will be 3111......