A determined gardener has 120 ft of fencing material. He wants to enclose a rectangular garden in his backyard, and wants an area that is enclosed to be at least 800 ft². What are the possible length of the garden?
A square has the largest area for perimeter length.
120/4=30 length of a side of the square
30^2=900 ft^2 largest area.
.
(30+x)(30-x)=800 Let x be the increase in length (or the decrease in width)
900-x^2=800
-x^2+100=0
x^2-100=0 multiply each side by -1
(x-10)(x+10)=0
x=10
40 x 20 is the longest 800 ft^2 area rectangle that can be built.
.
The longest length is 40 ft and the shortest is 30 ft.
Brainliest pls
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yurrygimenez22
If the product of two consecutive odd integers is represented by y=x(x+2), then what is the minimum product? What are the two integers?
yurrygimenez22
pwedeng pa-answer na rin po nito? kung alam nyo lng po
MiraQ
Here we have been given that the product of two positive consecutive odd integers is 483 and we are asked to determine such two integers. Hence, the two consecutive odd positive integers are 21 and 23.
annsubong222
12 meters by 10 meters and its perimeter is 44 meters
Answers & Comments
A square has the largest area for perimeter length.
120/4=30 length of a side of the square
30^2=900 ft^2 largest area.
.
(30+x)(30-x)=800 Let x be the increase in length (or the decrease in width)
900-x^2=800
-x^2+100=0
x^2-100=0 multiply each side by -1
(x-10)(x+10)=0
x=10
40 x 20 is the longest 800 ft^2 area rectangle that can be built.
.
The longest length is 40 ft and the shortest is 30 ft.
Brainliest pls