Answer:

hope this helps !

given -

s¹ - 1km t¹ - 1hr

s² - 0.5km. t² - 1hr

s³ - 0.3 km t³ - 1hr

average speed = total distance/ total time

total distance - 1.8km

total time- 3hr

(i) km/h

1.8/3 = 0.6km/hr

(ii) m/s

s= 1.8× 1000= 1800m

t= 3×60/3600 = 180/360 = 20m/s