B = μ0/4π x μ0Ni/2r = 2π x 10 ^ −7 x 100 x 0.1 / 5 x 10 ^ -2 = 2π x 10 ^ -7 x 10 / 5 x 10 ^ -2 = 2π x 10 ^ -7 +2 x 10 / 5 = 2π x 10 ^ -5 x 10 / 5 = 2π x 10 ^ -5 x 2 B = 4π x 10^ -5
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Answers & Comments
Verified answer
Answer:
The current circulating in the coil is I=0.1 A.
The number of turns in the coil is N=100 turns
The radius of the coil is r=5 cm
The magnetic field at the center of coil is:
B=
4π
μ
0
.
2r
μ
0
Ni
=
5×10
−2
2π×10
−7
×100×0.1
=4π×10
−5
Tesla
Explanation:
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Answer:
4π x 10^ -5
Explanation:
Given:
The current circulating in the coil is I=0.1 A.
The number of turns in the coil is N=100 turns
The radius of the coil is r = 5 cm
The magnetic field at the center of coil is:
B = μ0/4π x μ0Ni/2r
= 2π x 10 ^ −7 x 100 x 0.1 / 5 x 10 ^ -2
= 2π x 10 ^ -7 x 10 / 5 x 10 ^ -2
= 2π x 10 ^ -7 +2 x 10 / 5
= 2π x 10 ^ -5 x 10 / 5
= 2π x 10 ^ -5 x 2
B = 4π x 10^ -5
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