A cubical box has each edge 10 cm and another cuboidal box is 12.5cm long, 10 cm wide and 8 cm high (i) Which box has the greater lateral surface area and by how much? (ii) Which box has the smaller total surface area and by how much?
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(i) Lateral surface area of cube =4edge^ 2
=4(10)^ 2
=400
lateral surface area of cuboid 1 = 2h * (1 + b)
2 * 8 * (12.5 + 10)
=16*22.5 =360
So, the lateral surface area of the cube is larger by (400-360=40)cm^ 2
(ii) Total surface area of cube =6edge^ 2
=6(10)^ 2 =600
lateral surface area of cuboid d = 2(lb(+ b) * h + hl)
2(12.5 * 10 + 10 * 8 + 8 * 12.5)
=2(125+80+100) =610
So, the total surface area of cuboid is larger by (610-600=10)cm^ 2
Answer:
Answer:
Step-by-step explanation:
(i) Lateral surface area of cube =4edge^ 2
=4(10)^ 2
=400
lateral surface area of cuboid 1 = 2h * (1 + b)
2 * 8 * (12.5 + 10)
=16*22.5 =360
So, the lateral surface area of the cube is larger by (400-360=40)cm^ 2
(ii) Total surface area of cube =6edge^ 2
=6(10)^ 2 =600
lateral surface area of cuboid d = 2(lb(+ b) * h + hl)
2(12.5 * 10 + 10 * 8 + 8 * 12.5)
=2(125+80+100) =610
So, the total surface area of cuboid is larger by (610-600=10)cm^ 2