We have,
Now we know that, the formula for resistance is;
= R = ρ L/A
= 5 = 1.5 × 10-⁸ × L /πr²
= 5 × 10⁹/15 = L /3.14 × 10-³/2
= 10⁹/3 = L /1.57× 10-³
= 10⁹ × 157 × 10-² × 10-³/3
= 10⁹ × 157 × 10-⁵/3
= 52.3 × 10⁴ m
Therefore, the length of the conductor is 52.3 × 10⁴ m.
Now,if the diameter will be halfed then;
As, the length is reduced to half, thus the resistance will also be halfed.
__________________________
Thank youu!! :))
Answer:
neend nhi aa rahi
btw bruhh means .
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Answers & Comments
We have,
Now we know that, the formula for resistance is;
= R = ρ L/A
= 5 = 1.5 × 10-⁸ × L /πr²
= 5 × 10⁹/15 = L /3.14 × 10-³/2
= 10⁹/3 = L /1.57× 10-³
= 10⁹ × 157 × 10-² × 10-³/3
= 10⁹ × 157 × 10-⁵/3
= 52.3 × 10⁴ m
Therefore, the length of the conductor is 52.3 × 10⁴ m.
Now,if the diameter will be halfed then;
As, the length is reduced to half, thus the resistance will also be halfed.
__________________________
Thank youu!! :))![\; \;](https://tex.z-dn.net/?f=%5C%3B)
Answer:
neend nhi aa rahi
btw bruhh means .