Answer:

Here,

f

=

6

c

m

u

=

−

4

c

m

h

o

=

0.5

c

m

Using lens formula,

1

v

−

1

u

=

1

f

⇒

1

v

−

1

−

4

=

1

6

⇒

v

=

−

12

c

m

Now,

m

=

v

u

=

h

i

h

o

⇒

−

12

−

4

=

h

i

0.5

c

m

⇒

h

i

=

1.5

c

m

Hence, the image is virtual, erect and enlarged.

Explanation:

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