Explanation:
Let the radius of both the cone and hemisphere be r.
Given that, volume of both the cone and hemisphere are equal.
Therefore,
1/3πr²h = 2/3πr³
1/3r²h = 2/3r³
h = 2/3 x 3 x r³ x 1/r²
h = 2r ---- (eq.1)
Now, height of the cone is 2r (from eq.1) and the radius of the hemisphere is r.
The ratio is:
→ 2r : r
= 2 : 1
The required ratio is 2 : 1.
This can be represented as 2/1.
The sum of numerator and denominator is: 2 + 1 = 3
Formulae used:
Volume of hemisphere: 2/3πr³
Volume of cone: 1/3πr²h
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3
Explanation:
Let the radius of both the cone and hemisphere be r.
Given that, volume of both the cone and hemisphere are equal.
Therefore,
1/3πr²h = 2/3πr³
1/3r²h = 2/3r³
h = 2/3 x 3 x r³ x 1/r²
h = 2r ---- (eq.1)
Now, height of the cone is 2r (from eq.1) and the radius of the hemisphere is r.
The ratio is:
→ 2r : r
= 2 : 1
The required ratio is 2 : 1.
This can be represented as 2/1.
The sum of numerator and denominator is: 2 + 1 = 3
Formulae used:
Volume of hemisphere: 2/3πr³
Volume of cone: 1/3πr²h
I have attached the answer. please check. i hope it was useful.
please mark me the brainliest.