image will be 30cm beyond the lens or front of the mirror

magnification (m) = -3 (real image)

object distance (u) = -10

m=v/u

v=m*u

v=(-3) *(-10)

v=30cm

Answer:

Here, linearmagnification (m) = - 3 (Negative sign forreal image, which is inverted) Objectdistance Image distance As The image islocated at 30 cm in front of the mirror.