A compound a molecular formula = C2H4O2 react with Na metal to form a compoundB and evalves a gas which burns with a pop sound compound A on treatment with an alcohol C in the presence of an acid forms a sweet smelling compound D molecular formula= C3H6O2. B is also produced on addition of Naoh solution gives B and C . Identify A,B,C,D and write down the reaction involved.
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The compound 'A' is the ethanoic acid (CH3COOH) which forms the compound B after reaction with the metal Na.
The compound formed 'B' is the sodium acetate (CH3COONa).
The alcohol 'C' is the methanol (CH3OH).
The sweet smelling substance 'D' is Methyl acetate or ester (CH3COOCH3).
The reactions that are involved are -
1. 2Na + 2CH3COOH -------> 2CH3COONa + Hydrogen gas.
2. CH3OH + CH3COOH + H2SO4 --------> water + CH3COOCH3
3. NaOH + CH3COOH + H2SO4 ---------> CH3COONa + water
4. CH3COOCH3 + NaOH ---------> CH3OH + CH3COONa
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Compound A is ethanoic acid compound b is sodium ethanoate compound C is ethanol compound d is ethyl ethanoate now it is easy to find out the reaction involved