A clock while keeping correct time at 30°C has a pendulum rod made of brass. The number of seconds it gains or loses per second when the temperature falls to 10°C is NEED IT URGENT! SPAM = REPORT !!
The rate at which a clock gains or loses time due to temperature changes is determined by the coefficient of thermal expansion of the material used for the pendulum rod. Brass has a coefficient of thermal expansion, which means it expands or contracts with temperature changes.
To calculate the change in timekeeping due to temperature, you can use the formula:
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The rate at which a clock gains or loses time due to temperature changes is determined by the coefficient of thermal expansion of the material used for the pendulum rod. Brass has a coefficient of thermal expansion, which means it expands or contracts with temperature changes.
To calculate the change in timekeeping due to temperature, you can use the formula:
[tex]{ \red{ \boxed{ \tt \: Δt = L \times α \times ΔT}}}[/tex]
Where:
Let's assume:
Now, plug these values into the formula:
[tex] \sf \: Δt = 1 × (19 \times 10^{-6}) × 20[/tex]
[tex]{ \boxed{ \bold{Δt ≈ 0.00038 \: seconds \: per \: second}}}[/tex]
So, the clock will gain or lose approximately 0.00038 seconds per second when the temperature falls from 30°C to 10°C.
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[tex]{ \orange{ \sf \: hope \: it \: helps \: you}}[/tex]