Answer:
[tex]{\huge{\underline{\small{\mathbb{\pink{REFER \ TO \ THE \ ATTACHMENT}}}}}}[/tex]
Let AB the chord.
In right angled triangle AOM, given OA=13cm=radius.
OM= distance of centre O from the chord = 12cm
By Pythagoras theorem
[tex] {am}^{2} = {ao}^{2} - {om}^{2} \\ \\ = {13}^{2} - {12}^{2} \\ \\ = 25 \\ \\ {am}^{2} = 25 \\ \\ am = 5cm [/tex]
AM=5cm
Therefore, chord AB =2(AM)
=2×5=10cm
Hope it helps you from my side
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Answers & Comments
Answer:
Hence, the length of the chord will be 10 cm.
Verified answer
Answer:
[tex]{\huge{\underline{\small{\mathbb{\pink{REFER \ TO \ THE \ ATTACHMENT}}}}}}[/tex]
Let AB the chord.
In right angled triangle AOM, given OA=13cm=radius.
OM= distance of centre O from the chord = 12cm
By Pythagoras theorem
[tex] {am}^{2} = {ao}^{2} - {om}^{2} \\ \\ = {13}^{2} - {12}^{2} \\ \\ = 25 \\ \\ {am}^{2} = 25 \\ \\ am = 5cm [/tex]
AM=5cm
Therefore, chord AB =2(AM)
=2×5=10cm
Hope it helps you from my side