A charge 'q' is moved from a point A above a dipole of dipole moment 'p' to a point B below the dipole in equatorial plane without acceleration. Find the work done in the process.
It is seen that potential due to dipole at any point on equipotential line is equatorial plane is zero. From the figure, point A and B lies in equatorial plane of dipole, where work done in moving charge 'q' from point A and B without acceleration will be zero.
Answers & Comments
Hey !!
No work is done.
W = qVab = q × 0 = 0
DETAILED EXPLANATION
It is seen that potential due to dipole at any point on equipotential line is equatorial plane is zero. From the figure, point A and B lies in equatorial plane of dipole, where work done in moving charge 'q' from point A and B without acceleration will be zero.
Good luck !!
Verified answer
Work= 0 juleNo work is done. Becoz for a dipole equitorial line is equipotential line.
Work = potential difference * charge
Potential difference between two given location is zero