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SOLUTION:

Step 1: List the given values.

To convert the temperature from degree Celsius to kelvin, add 273 to the temperature expressed in degree Celsius.

[tex]\begin{aligned} P_1 & = \text{0.800 atm} \\ T_1 & = 25^{\circ}\text{C} = \text{298 K} \\ P_2 & = \text{2.00 atm} \end{aligned}[/tex]

Step 2: Calculate the final temperature (in degree Celsius) by using Gay-Lussac's law.

To convert the temperature from kelvin to degree Celsius, subtract 273 from the temperature expressed in kelvin.

[tex]\begin{aligned} \frac{P_1}{T_1} & = \frac{P_2}{T_2} \\ T_2P_1 & = T_1P_2 \\ \frac{T_2P_1}{P_1} & = \frac{T_1P_2}{P_1} \\ T_2 & = \frac{T_1P_2}{P_1} \\ & = \frac{(\text{298 K})(\text{2.00 atm})}{\text{0.800 atm}} \\ & = \text{745 K} \\ & = \boxed{472^{\circ}\text{C}} \end{aligned}[/tex]

Hence, I can raise the temperature of the gas up to 472°C without bursting the vessel.

[tex]\\[/tex]

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