A carpenter has two water pipes which are 60dm and 72dm long, respectively. He cuts them into equal lengths. What is the greatest possible length of each pipe?
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What are the given?
What operation to be used?
What is the solution?
What is the answer?
What is asked?
What are the given?
What operation to be used?
What is the solution?
What is the answer?
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WHAT IS ASKED? -What is the greatest possible length of each pipe?
What are the given? -The given is 60dm and 72dm
SOLUTION : The greatest possible length of each pipe is equal to the HCF of 60 dm & 62 dm . To find the HCF of these numbers use prime factorization method of calculating HCF. Hence, the greatest possible length of each pipe is 12 dm.
What is the answer - 12 dm
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