Answer:

total number- 18

numbers divisible by 3 or 7- 3,6,9,12,15,18,7,14

in total, numbers divisible by 3 or 7- 8

P(E)- 8/18=4/9=0.4

The probability of getting the number which is divisible by 3 or 7 is 4/9

Given :

A card is drawn randomly from the number cards numbered from 3 to 20

To find :

The probability of getting the number which is divisible by 3 or 7

Solution :

Step 1 of 3 :

Find total number of possible outcomes

A card is drawn randomly from the number cards numbered from 3 to 20

Total number of cards = 18

So total number of possible outcomes = 18

Step 2 of 3 :

Calculate number of possible outcomes for the event

Let A be the event that of getting the number which is divisible by 3 or 7.

The numbers from 3 to 20 which are divisible by 3 or 7 are 3 , 6 , 7 , 9 , 12 , 14 , 15 , 18

There are 8 such numbers which are divisible by 3 or 7

Total number of possible outcomes for the event A = 8

Step 3 of 3 :

Find the probability

∴ The probability that of getting the number which is divisible by 3 or 7

= P(A)

[tex]\displaystyle \sf{ = \frac{Number \: of \: favourable \: cases \: to \: the \: event \: A }{Total \: number \: of \: possible \: outcomes }}[/tex]

[tex] \displaystyle \sf{ = \frac{8}{18} }[/tex]

[tex] \displaystyle \sf{ = \frac{4}{9} }[/tex]

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