Answer:
125m
Explanation:
u=25m/sec
Distance it travels in 5sec
Distance travelled before the brakes are applied= 25*5=125m
After 5 sec brakes are applied
It then comes to rest in 10sec
u=25m/s
v=0(as it comes to rest)
t=10
a=change in velocity/time=-25/10=-2.5
s=?
s=ut+at^2/2
s=25*10+(-2.5)(100)/2=250-125
The distance it travels after the brakes are applied is 125m
Comments:
Kon'nichiwa! Sore ga yakunitateba saiwai! ❤
( Hello! Hope it helps! ❤ )
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Answers & Comments
Answer:
125m
Explanation:
u=25m/sec
Distance it travels in 5sec
Distance travelled before the brakes are applied= 25*5=125m
After 5 sec brakes are applied
It then comes to rest in 10sec
u=25m/s
v=0(as it comes to rest)
t=10
a=change in velocity/time=-25/10=-2.5
s=?
s=ut+at^2/2
s=25*10+(-2.5)(100)/2=250-125
The distance it travels after the brakes are applied is 125m
Comments:
Kon'nichiwa! Sore ga yakunitateba saiwai! ❤
( Hello! Hope it helps! ❤ )
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