Answer:
TIME = Distance/speed
So,
t¹=
[tex] \frac{20}{40} = \frac{1}{2} h[/tex]
t²=
[tex] \frac{24}{56} = \frac{3}{7} h[/tex]
t³=
[tex] \frac{27}{45} = \frac{3}{5} h[/tex]
Average Speed =
[tex] \frac{total \: distance}{total \: time} [/tex]
[tex] \frac{20 + 24 + 27}{ \frac{1}{2} + \frac{3}{7} + \frac{3}{5} } [/tex]
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Answer:
TIME = Distance/speed
So,
t¹=
[tex] \frac{20}{40} = \frac{1}{2} h[/tex]
t²=
[tex] \frac{24}{56} = \frac{3}{7} h[/tex]
t³=
[tex] \frac{27}{45} = \frac{3}{5} h[/tex]
Average Speed =
[tex] \frac{total \: distance}{total \: time} [/tex]
So,
[tex] \frac{20 + 24 + 27}{ \frac{1}{2} + \frac{3}{7} + \frac{3}{5} } [/tex]
= 46.44 km/h