Explanation:
ANSWER
Given that,
Intial velocity u=0m/s
Final velocity v=54km/h=54×
18
5
=15m/s
Time t=2min=120s
Now, put the value in equation of motion
The acceleration is
v=u+at
a=
t
v−u
120
15−0
a=o.125m/s
2
Now, again from equation of motion
The distance is
s=ut+
1
at
s=0+
×0.125×120×120
s=900m
Hence, the acceleration is 0.125m/s
and distance is 900m
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Answers & Comments
Explanation:
ANSWER
Given that,
Intial velocity u=0m/s
Final velocity v=54km/h=54×
18
5
=15m/s
Time t=2min=120s
Now, put the value in equation of motion
The acceleration is
v=u+at
a=
t
v−u
a=
120
15−0
a=o.125m/s
2
Now, again from equation of motion
The distance is
s=ut+
2
1
at
2
s=0+
2
1
×0.125×120×120
s=900m
Hence, the acceleration is 0.125m/s
2
and distance is 900m