A car of mass 100kg is moving with a certain velocity. It is brought to rest by the application of brakes, within a distance of 10m when the average resistance being offered to it is 250N.What was the velocity of the motor car?
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Answer:
5√2 m/s
Explanation:
m= 100 kg
s= 10 m
f=-250N
initial velocity=?
final velocity=0
acceleration= F/M=-250/100=-2.5m/s2
we have v2-u2= 2as
u2= v2-2as
= 0-2(-2.5)×10 m2/s2
=50 m2/s2
u=√50
u=√25×2
u=5√2m/s