Step-by-step explanation:
speed u= 18 km/h = 18000m /60*60sec = 18000/3600 m/s=3 m/s
2) final speed v=0 m/s
so accn a= v -u / t
a = - 3/5 = .6 m/s^2(retardation)
3)speed of car after 2 sec of applying break= at= .6*2= 1.2 m/s
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Verified answer
Step-by-step explanation:
speed u= 18 km/h = 18000m /60*60sec = 18000/3600 m/s=3 m/s
2) final speed v=0 m/s
so accn a= v -u / t
a = - 3/5 = .6 m/s^2(retardation)
3)speed of car after 2 sec of applying break= at= .6*2= 1.2 m/s