. A car initially at rest, picks up a velocity of 72 kmh-' in 20 seconds. If the mass of the car is 1000 kg, find (i) Force developed by its engine (ii) Distance covered by the car.
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Answer:
v = 72 kmph = 72*5/18 = 20m/s. OR... F = change in momentum/ t. Distance traveled s = t *(v+u)/2 = 20 * 20/2 = 200m.
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v = 72 kmph = 72*5/18 = 20m/s. OR... F = change in momentum/ t. Distance traveled s = t *(v+u)/2 = 20 * 20/2 = 200m