A candle 5 cm high is placed 30 cm from a concave mirror whose radius of curvature is 40 cm. Find the image distance, image height and the nature of image. With Solution
Pls I need the answer
Real answer= follow + brainliest
Nonsense answer= report
Pls I need the answer
Real answer= follow + brainliest
Nonsense answer= report
Answers & Comments
¹/f= ¹/do + ¹/di
where:
f= focal length
do= distance of object
di=s distance of image
f=R/2
f=40/2
f=20
(reverse the formula to find the di)
¹/di= ¹/f - ¹/do
¹/di= (¹/20cm) - (¹/30cm)
¹/di= (0.05cm-0.0333333cm)
¹di= 0.0166667cm
di=1/0.0166667cm
59.99cm or 60cm
di=60cm
nature of image is REAL since it is positive
Height of Image:
hi/ho= -di/do
where:
hi= height of an image
ho=height of an object
di=distance of an image
do=distance of an object
hi/5cm= -60cm/30cm
hi/5cm= -2cm
hi= -2cm × 5cm
hi= -10cm
since it was negative the height of an image is INVERTED
Final Answer:
Image distance (di)=60cm
Image height (hi)= -10cm
Nature of image is REAL but INVERTED