Answer:
0.4ms-1 is the answer.
Step-by-step explanation:
As the speed does not remain constant throughout the journey the motion is non-uniform.
Total distance travelled in going and coming back,
d=30m+30m=60m
Total time taken in going and coming back
t=1min+1.5min=2.5min=2.5×60s=150s
Average speed = Total time of travel
Total distance travelled = 150s60m
=0.4ms −1
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Verified answer
Answer:
0.4ms-1 is the answer.
Step-by-step explanation:
As the speed does not remain constant throughout the journey the motion is non-uniform.
Total distance travelled in going and coming back,
d=30m+30m=60m
Total time taken in going and coming back
t=1min+1.5min=2.5min=2.5×60s=150s
Average speed = Total time of travel
Total distance travelled = 150s60m
=0.4ms −1