A book exhibition was held for four days in a school. The number of tickets sold at the counter on the first, second, third and final day was respectively 1094. 1812. 2050 and 2751. Find the total number of tickets sold on all the four days.
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As it is asking for the total no.of tickets sold on all the four days , we will add all the no. of tickets sold on first, second, third and fourth day. So, 1094 +1812+2050+2751. So the sum will be 7707.
So your answer is 7,707
total no of tickets =1094+1812+2050+2751=7707
= 7707