Verified answer

Answer:

[tex]\huge\mathbb{ \underline{ANSWER:}} [/tex]

[tex]\begin{gathered}\huge\orange{\overline{\qquad\qquad\qquad\qquad \: \: \: }} \\ \color {red}{᯽}\color {orange}{᯽}\color {yellow}{᯽}\color {lime}{᯽}\color {green}{᯽}\color {cyan}{᯽}\color {aquamarine}{᯽}\color {indigo}{᯽}\color {blue}{᯽}\color {violet}{᯽}\color {blueviolet}{᯽}\color {pink}{᯽}\color {magenta}{᯽} \color {brown}{᯽}\color {gray}{᯽}\color {black}{᯽}\color {red}{᯽}\color {orange}{᯽}\color {yellow}{᯽}\color {lime}{᯽}\color {green}{᯽}\color {cyan}{᯽}\color {aquamarine}{᯽}\color {indigo}{᯽}\color {blue}{᯽}\color {violet}{᯽}\color {blueviolet}{᯽}\color {pink}{᯽}\color {magenta}{᯽} \color {brown}{᯽}\color {gray}{᯽}\end{gathered} [/tex]

The interest is D. 600

To find the internet use the given formula:

• [tex]\sf \: I = P×r×t[/tex]

Where,

• I is the interest
• P is the principal
• R is the rate
• T is time

Given,

• P - 1,000
• R - 4%
• T - 15 yrs
• I - ?

Solving,

[tex]\begin{gathered} \sf \: I \: = Prt \\ \\ \sf \: I= (1000)(0.04)(15) \\ \\ \sf \: I = 40 \times 15 \\ \\ \sf \: I = 600\end{gathered} [/tex]

Therefore, the interest is 600

[tex]\begin{gathered}\huge\orange{\overline{\qquad\qquad\qquad\qquad \: \: \: }} \\ \color {red}{᯽}\color {orange}{᯽}\color {yellow}{᯽}\color {lime}{᯽}\color {green}{᯽}\color {cyan}{᯽}\color {aquamarine}{᯽}\color {indigo}{᯽}\color {blue}{᯽}\color {violet}{᯽}\color {blueviolet}{᯽}\color {pink}{᯽}\color {magenta}{᯽} \color {brown}{᯽}\color {gray}{᯽}\color {black}{᯽}\color {red}{᯽}\color {orange}{᯽}\color {yellow}{᯽}\color {lime}{᯽}\color {green}{᯽}\color {cyan}{᯽}\color {aquamarine}{᯽}\color {indigo}{᯽}\color {blue}{᯽}\color {violet}{᯽}\color {blueviolet}{᯽}\color {pink}{᯽}\color {magenta}{᯽} \color {brown}{᯽}\color {gray}{᯽}\end{gathered} [/tex]

Step-by-step explanation:

[tex]\begin{gathered}\boxed{ \bold{ \orange{ \: CARRY \: ON \: LEARNING\: }}}\\\end{gathered} [/tex]

[tex]\begin{gathered}\boxed{ \bold{ \pink{ \: MissCookie \: }}}\\\end{gathered} [/tex]

[tex]\begin{gathered}\boxed{ \bold{ \blue{ \: ฅ⁠^⁠v•⁠ﻌ⁠•⁠^⁠vฅ\: }}}\\\end{gathered} [/tex]

Answer:

The interest is D. 600

Step-by-step explanation:

To find the internet use the given formula:

\sf \: I = P×r×tI=P×r×t

Where,

I is the interest

P is the principal

R is the rate

T is time

Given,

P - 1,000

R - 4%

T - 15 yrs

I - ?

Solving,

\begin{gathered} \sf \: I \: = Prt \\ \\ \sf \: I= (1000)(0.04)(15) \\ \\ \sf \: I = 40 \times 15 \\ \\ \sf \: I = 600\end{gathered}

I=Prt

I=(1000)(0.04)(15)

I=40×15

I=600

Therefore, the interest is 600

#CarryOnLearning