a body of mass 3 kg is dropped from a tower of height 250m,then its kinetic energy after 3s will be????
Answers & Comments
careerheights
Given that , m = 3kg , u = 0 , t = 3 sec , a = g = 9.8m/s2 So velocity at t = 3sec v = u +a t = 0 + 9.8(3) = 29.4 m/s Kinetic energy = 1/2 m v2 = 1/2 (3) (29.4)2 = 1296.54 J
Answers & Comments
So velocity at t = 3sec
v = u +a t
= 0 + 9.8(3)
= 29.4 m/s
Kinetic energy = 1/2 m v2
= 1/2 (3) (29.4)2
= 1296.54 J