S = ut + at2/2
4 = 0x2 + a x 22/2 (As initial velocity (u) was 0)
4 = 4a/2
a = 8/4
Therefore a = 2
Force-mass-acceleration
F=2 X 2
F=4N.
Therefore answer is 4N.
Answer:
4) 4N
Explanation:
Apply second equation of motion
[tex]s = ut \: + \: \frac{1}{2} at {}^{2} [/tex]
Here s = 4, t = 2 and u = 0. So a = 2m/s^2.
F = ma => F = 2kg × 2m/s^2. = 4N. Therefore 4) 4N.
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Answers & Comments
S = ut + at2/2
4 = 0x2 + a x 22/2 (As initial velocity (u) was 0)
4 = 4a/2
a = 8/4
Therefore a = 2
Force-mass-acceleration
F=2 X 2
F=4N.
Therefore answer is 4N.
Verified answer
Answer:
4) 4N
Explanation:
Apply second equation of motion
[tex]s = ut \: + \: \frac{1}{2} at {}^{2} [/tex]
Here s = 4, t = 2 and u = 0. So a = 2m/s^2.
F = ma => F = 2kg × 2m/s^2. = 4N. Therefore 4) 4N.