A body of mass 1 kg is placed at a distance of 2m from another body of mass 10kg. At what distance from the body of 1 kg, another body of mass 5 kg be placed so that the net force of gravitation acting on the body of mass 1 kg is zero?
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
answer:
Gravitational Force Equation: The gravitational force between two objects is given by the formula:
F = G * (m1 * m2) / r^2
where:
F is the gravitational force (measured in Newtons)
G is the gravitational constant (6.6743 x 10^-11 N * m^2 / kg^2)
m1 and m2 are the masses of the two objects (measured in kilograms)
r is the distance between the centers of the objects (measured in meters)
Balancing Forces: We want the net force on the 1 kg mass to be zero. This means the forces due to the 10 kg and 5 kg masses should cancel each other out. Therefore, we can set up an equation:
G * (10 kg * 1 kg) / 2^2 = G * (5 kg * 1 kg) / x^2
where x is the unknown distance between the 1 kg and 5 kg masses.
Solve for x: Simplifying the equation and rearranging, we get:
x^2 = 5 * 2^2 / 10 = 2
Then, taking the square root of both sides:
x = √2