Verified answer

Explanation:

To calculate the pressure exerted on the table by the block in each case, we need to divide the force exerted by the block (weight) by the area of contact between the block and the table.

Let's calculate the pressure for each case:

(i) Base dimensions: 5cm x 2cm

Area of contact (A): 5cm x 2cm = 10cm² = 0.001m² (converting to square meters)

Weight (force) of the block: 5kgf (kilogram-force)

1 kilogram-force (kgf) = 9.81 Newtons (N)

Weight (force) of the block in Newtons (W): 5kgf x 9.81 N/kgf = 49.05 N

Pressure (P) = W / A

P = 49.05 N / 0.001 m² = 49,050 N/m²

(ii) Base dimensions: 2cm x 1cm

Area of contact (A): 2cm x 1cm = 2cm² = 0.0002m² (converting to square meters)

Weight (force) of the block: 5kgf (kilogram-force)

Weight (force) of the block in Newtons (W): 5kgf x 9.81 N/kgf = 49.05 N

Pressure (P) = W / A

P = 49.05 N / 0.0002 m² = 245,250 N/m²

(iii) Base dimensions: 1cm x 5cm

Area of contact (A): 1cm x 5cm = 5cm² = 0.0005m² (converting to square meters)

Weight (force) of the block: 5kgf (kilogram-force)

Weight (force) of the block in Newtons (W): 5kgf x 9.81 N/kgf = 49.05 N

Pressure (P) = W / A

P = 49.05 N / 0.0005 m² = 98,100 N/m²

Therefore, the pressure exerted on the table in each case is as follows:

(i) 49,050 N/m²

(ii) 245,250 N/m²

(iii) 98,100 N/m²