A balloon has a volume of 0.546L at 365K The volume of the balloon is decreased yo 0.338L describe the new temperature? what
Gas Law Used
T2
2. A sample of gas accupies a volume of 1.31L When the volume increases to 2.7 L the new pressure is 243.3 atm what was the original pressure. What Gas Law used
P1
3.Carbon dioxide gas expands from 9.3 to 10.4 the final temperature is 43C determined the initial temperature if the pressure remains constant Gas law Used
T1
4. A 38.4 L tank of ammonia has a pressure of 11.3kPa. Calculate the volume of the ammonia if is pressure is change 9.8kPa while its temperature remain constant What is the gas law used
Gas Law Used
T2
2. A sample of gas accupies a volume of 1.31L When the volume increases to 2.7 L the new pressure is 243.3 atm what was the original pressure. What Gas Law used
P1
3.Carbon dioxide gas expands from 9.3 to 10.4 the final temperature is 43C determined the initial temperature if the pressure remains constant Gas law Used
T1
4. A 38.4 L tank of ammonia has a pressure of 11.3kPa. Calculate the volume of the ammonia if is pressure is change 9.8kPa while its temperature remain constant What is the gas law used
Answers & Comments
Verified answer
Answer:
1. Gas Law Used: Charles's Law
Using the formula, V1/T1 = V2/T2, we can solve for T2:
V1 = 0.546L
T1 = 365K
V2 = 0.338L
T2 = (V2/T2) * T1
T2 = (0.338/0.546) * 365K
T2 = 225.7K
Therefore, the new temperature is 225.7K.
2. Gas Law Used: Boyle's Law
Using the formula, P1V1 = P2V2, we can solve for P1:
V1 = 1.31L
P2 = 243.3 atm
V2 = 2.7L
P1 = (P2V2)/V1
P1 = (243.3 atm * 2.7L)/1.31L
P1 = 502.5 atm
Therefore, the original pressure was 502.5 atm.
3. Gas Law Used: Charles's Law
Using the formula, V1/T1 = V2/T2, we can solve for T1:
V1 = 9.3 L
T2 = 316K
V2 = 10.4 L
T1 = (V1/T1) * T2
T1 = (9.3/10.4) * 316K
T1 = 282.8K
Therefore, the initial temperature was 282.8K.
4. Gas Law Used: Boyle's Law
Using the formula, P1V1 = P2V2, we can solve for V2:
V1 = 38.4L
P1 = 11.3 kPa
P2 = 9.8 kPa
V2 = (P1V1)/P2
V2 = (11.3 kPa * 38.4L)/9.8 kPa
V2 = 44.1L
Therefore, the volume of ammonia is 44.1L.
Explanation:
#CARRYONLEARNING
#BrainlyPH