A ball of mass 700 g is dropped from a height of it is just going to touch the floor? 20 m. What will be the momentum of the ball when it is just going to touch the floor?
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Explanation:
p=mv
p=.7×v
v²=u²+2as
v²=0+2×9.8×20
v²=392
v=√392
v=2√73
p=1.4√73 kg/ms
p = 13.9 kg.m/s
Explanation:
Momentum = mass * velocity
p = mv
To find the velocity use Newton’s 3rd equation of motion.
2as = vf^2 - vi^2
Since the body started from rest vi = 0.
2as = vf^2
vf = (2as)^1/2
Since body is falling downward acceleration is due to gravity a = g = 9.8 m/s^2.
vf = (2*9.8*20)^1/2
vf = 19.8 m/s
p = 0.7 * 19.8
p = 13.9 kg.m/s