A ball is projected from top of a tower of height 80 m with initial velocity 50 metre per second at an angle 37 degree with horizontal find range and time of flight
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Answer:
the acceleration due to gravity is vertical so the horizontal component V
x
=30m/s will remain constant.
and the vertical component will get increased from 0 to v given by
2gh
=
2×10×80
=40m/s
so the net velocity will be V= v 2 +v x2= 1600+900
=50m/s
Explanation:
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