Verified answer

Given:

• Initial velocity,u = 6.0 m/s

• Final velocity, v = -4.4 m/s ( Given : rebounds horizontally )

• Time taken = 0.04 s

To be calculated:

Calculate the acceleration of given ball ?

Formula used:

Acceleration = change in velocity/Time taken

Solution:

Acceleration = change in velocity/time taken

Acceleration = v - u / t

★ Substituting the values in the above formula,we get

Acceleration = -4.4 - 6.0 / 0.04

= - 10.4 / 0.04

= - 1040 / 4

= -260 m/s²

Thus, the acceleration of given ball is -260 m/s².

• A ball hits horizontally (Initial Velocity) = 6m/s (Forward)
• It rebounds horizontally (Final Velocity) = -4.4 m/s (Forward) And 4.4 m/s (backward)
• The Ball is contact with the wall (Time Taken ) = 0.04 seconds

• The Acceleration of the Ball .

We Know that :

(Always  Initial velocity and final velocities are opposite in direction )

Now Put the Value in this Formula :

Therefore,

Acceleration of the Ball = 260 m/s² (Answer)