A bag contains 6 blue, 5 red and 9 white balls. One ball is drawn at random and then a second ball is drawn. Find the difference in probability of getting both the balls as white with and without replacement.
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Answers & Comments
correct answer is 99/7600
Given:
Number of red balls = 5
Number of white balls = 9
Number of blue balls = 6
Total number of balls = 20
Two balls are drawn one after another in random.
Formula used:
Probability = Favorable outcome
Total outcomes
Calculations:
Case -1 .... (Without replacement)
Case -2 .... (With replacement)
Required difference = 81/400 – 72/380 = 99/7600
Answer:
Answers is 99/7600
Step-by-step explanation:
Given:
Number of red balls = 5
Number of white balls = 9
Number of blue balls = 6
Total number of balls = 20
Two balls are drawn one after another in random.
Formula used:
Probability = Favorable outcome / Total outcomes
Calculations:
Case-1 [Without replacement]
Probability of getting the first ball as white = 9/20
Probability of getting the second ball as white = 8/19
Probability of getting both the balls as white = 9/20 × 8/19 = 72/380
Case-2 [With replacement]
Probability of getting the first ball as white = 9/20
Probability of getting the second ball as white = 9/20
Probability of getting both the balls as white = 9/20 × 9/20 = 81/400
Required difference = 81/400 – 72/380 = 99/7600
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