a, b, and c are different integers. The following relations are true about a, b, and c. i. abc = 36, ii. a + b + c = 11, iii. a? + b3 + c2 = 49 Find the values of a, b, and c
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Answer:
a=2
b=3
c=6
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2x3x6= 36
2+3+6= 11
2^2+3^2+6^2 = 4+9+36= 49
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