A. Assimilation (Time Frame: 20 minutes) Answer the following accordingly. 1. De...

Questions

October 2022 1 4 Report

A. Assimilation (Time Frame: 20 minutes)
Answer the following accordingly.
1. Describe the type of problems that require the law of cosines.
2. Can the law of cosines be used to solve any triangle for which two angles and a side are known? Explain your answer.
3. Can you site real life application of law of cosines? Describe how you can you apply the law of cosines in that situation. Give at least two situations.
V. ASSESSMENT (Time Frame: 40 minutes)
(Learning Activity Sheets for Enrichment, Remediation, or Assessment to be given on Weeks 3 and 6)
A. Solve the following triangles. Round to the nearest tenth.

B. Draw triangles given the indicated measures below and solve for the missing part using the law of cosines. Round the answers to the nearest tenth.
1. ∠A = 46, b = 11, c = 9
2. a = 8, b = 10, c = 13

Answers & Comments

RogeVincent1010

B.) Draw the given the indicated measure below and solve for the missing parts using the law of cosines.

${\color{orange}{\huge{\underbrace{\overbrace{\mathfrak{\:\:\:\:\:\:\:\:Answer:\:\:\:\:\:\:\:\:\:}}}}}}$

$______________________________$

$\small\color{black}{{\underline{\bold{ A.\:Solve\:the\: following\: triangle}}}}$

$\small\color{black}{{\underline{\bold{1.) {c}^{2} \sqrt{ {5}^{2} + {8}^{2} - 2(5)(8) \cos(125) } } } } } \\ = \small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:c=11.61\:\:\:\: }}}}$

$\small\color{black}{{\underline{\bold{\cos { }^{ - 1} = \frac{ {5}^{2} + {11.61}^{2} -{8}^{2} }{2(5)(11.61)} } } } } \\ =\small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:B=34.40\:\:\:\: }}}}$

$\small\color{black}{{\underline{\bold{ \cos { }^{ - 1} = \frac{ {11.61}^{2} + {8}^{2} - {5}^{2} }{2(11.61)(8)} } } } } \\ = \small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:A=20.67\:\:\:\: }}}}$

$\small\color{black}{{\underline{\bold{ 2) = \cos {}^{ - 1}=\frac{ {7}^{2} + {5}^{2} -{3}^{2} }{2(7)(5)} } } } } \\ = \small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:A=21.78\:\:\:\: }}}}$

$\small\color{black}{{\underline{\bold{ \cos {}^{ - 1} = \frac{ {5}^{2} + {3}^{2} - {7}^{2} }{2(5)(3)} } } } } \\ = \small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:B=120°\:\:\:\: }}}}$

$\small\color{black}{{\underline{\bold{ \cos { }^{ - 1} = \frac{ {3}^{2} + {7}^{2} - {5}^{2} }{2(3)(7)} } } } } \\ =\small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:C=38.21\:\:\:\: }}}}$

$\small\color{black}{{\underline{\bold{3.) \: {c}^{2} \sqrt{ {9}^{2} + {9}^{2} - 2(9)(9) \cos(115) } } } } } \\ = \small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:c=15.18\:\:\:\: }}}}$

$\small\color{black}{{\underline{\bold{ \cos {}^{ - 1} = \frac{ {15.18}^{2} + {9}^{2} - 9 }{2(15.18)(9)} } } } } \\ =\small\color{black}{{{\boxed{\tt\red{} \:\:\:\:\:\:\:\:\:\:B=32.50\:\:\:\: }}}}$