Answer: 15 days
Step-by-step explanation: please find the attachment
Hope it helps
Given :
A and B working together can do a work in 6 days
To Find :
If A takes 5 days less than B to finish the work,in how many days B alone can do the work ?
Solution:
Let x be the no. of days taken by B to complete the work
A takes 5 days less than B to finish the work
So, A completes work in x-5 days
(A+B)'s 1 day work =
(A+B)'s 6 days work =
We are given that A and B working together can do a work in 6 days
So,
If B Complete work in 2 days
So, A completes work in day = x-5 = 2-5 = -3
No. of days cannot be negative
So, B completes work alone in 15 days
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Answers & Comments
Answer: 15 days
Step-by-step explanation: please find the attachment
Hope it helps
Given :
A and B working together can do a work in 6 days
To Find :
If A takes 5 days less than B to finish the work,in how many days B alone can do the work ?
Solution:
Let x be the no. of days taken by B to complete the work
A takes 5 days less than B to finish the work
So, A completes work in x-5 days
(A+B)'s 1 day work =![\frac{1}{x}+\frac{1}{x-5} \frac{1}{x}+\frac{1}{x-5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7Bx-5%7D)
(A+B)'s 6 days work =![6( \frac{1}{x}+\frac{1}{x-5}) 6( \frac{1}{x}+\frac{1}{x-5})](https://tex.z-dn.net/?f=6%28%20%5Cfrac%7B1%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7Bx-5%7D%29)
We are given that A and B working together can do a work in 6 days
So,![6( \frac{1}{x}+\frac{1}{x-5})= 1\\6(\frac{x-5+x}{x(x-5)})=1\\6(\frac{2x-5}{x(x-5)})=1\\12x-30=x^2-5x\\x^2-17x+30=0\\x^2-15x-2x+30=0\\(x-15)(x-2)=0\\x=15,2 6( \frac{1}{x}+\frac{1}{x-5})= 1\\6(\frac{x-5+x}{x(x-5)})=1\\6(\frac{2x-5}{x(x-5)})=1\\12x-30=x^2-5x\\x^2-17x+30=0\\x^2-15x-2x+30=0\\(x-15)(x-2)=0\\x=15,2](https://tex.z-dn.net/?f=6%28%20%5Cfrac%7B1%7D%7Bx%7D%2B%5Cfrac%7B1%7D%7Bx-5%7D%29%3D%201%5C%5C6%28%5Cfrac%7Bx-5%2Bx%7D%7Bx%28x-5%29%7D%29%3D1%5C%5C6%28%5Cfrac%7B2x-5%7D%7Bx%28x-5%29%7D%29%3D1%5C%5C12x-30%3Dx%5E2-5x%5C%5Cx%5E2-17x%2B30%3D0%5C%5Cx%5E2-15x-2x%2B30%3D0%5C%5C%28x-15%29%28x-2%29%3D0%5C%5Cx%3D15%2C2)
If B Complete work in 2 days
So, A completes work in day = x-5 = 2-5 = -3
No. of days cannot be negative
So, B completes work alone in 15 days